0.5x^2+2x-8-4x-t=0

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Solution for 0.5x^2+2x-8-4x-t=0 equation:


Simplifying
0.5x2 + 2x + -8 + -4x + -1t = 0

Reorder the terms:
-8 + -1t + 2x + -4x + 0.5x2 = 0

Combine like terms: 2x + -4x = -2x
-8 + -1t + -2x + 0.5x2 = 0

Solving
-8 + -1t + -2x + 0.5x2 = 0

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + -1t + -2x + 8 + 0.5x2 = 0 + 8

Reorder the terms:
-8 + 8 + -1t + -2x + 0.5x2 = 0 + 8

Combine like terms: -8 + 8 = 0
0 + -1t + -2x + 0.5x2 = 0 + 8
-1t + -2x + 0.5x2 = 0 + 8

Combine like terms: 0 + 8 = 8
-1t + -2x + 0.5x2 = 8

Add '2x' to each side of the equation.
-1t + -2x + 2x + 0.5x2 = 8 + 2x

Combine like terms: -2x + 2x = 0
-1t + 0 + 0.5x2 = 8 + 2x
-1t + 0.5x2 = 8 + 2x

Add '-0.5x2' to each side of the equation.
-1t + 0.5x2 + -0.5x2 = 8 + 2x + -0.5x2

Combine like terms: 0.5x2 + -0.5x2 = 0.0
-1t + 0.0 = 8 + 2x + -0.5x2
-1t = 8 + 2x + -0.5x2

Divide each side by '-1'.
t = -8 + -2x + 0.5x2

Simplifying
t = -8 + -2x + 0.5x2

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